-2x^2-10x+20=-3x

Solution for -2x^2-10x+20=-3x equation:

-2x^2-10x+20=-3x

We move all terms to the left:

-2x^2-10x+20-(-3x)=0

We get rid of parentheses

-2x^2-10x+3x+20=0

We add all the numbers together, and all the variables

-2x^2-7x+20=0

a = -2; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·(-2)·20
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{209}}{2*-2}=\frac{7-\sqrt{209}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{209}}{2*-2}=\frac{7+\sqrt{209}}{-4}
$